Economic of power generation 9
Question = A hydro electric plant costs RS 3000 per kW of installed capacity . The total annual charges consist of 5 % (F) as interest , depreciation at 2% (F) , operation and maintenance at 2 % (R) and insurance , rent etc , 1.5 % (R). Determine a suitable two part tariff if the losses in transmission and distribution are 12.5% and diversity of loads is 1.25 . Assume that maximum demand on the station is 80% of the capacity and annual load factor is 40% . What is the overall cost of generation per kWh ?
Solution = overall cost /kWh = total annual charges ÷ unit reaching the consumer ,
» Total annual charges = annual fixed charges + annual running charges ,
» annual fixed charges (A F.C ) = capital cost of plant × ( interest % + depreciation % ) /100 ,
» capital cost of plant = let installed capacity of the station kW × plant cost per kW , » 100 kW × 3000 RS = 3 × 10⁵ RS ,
» interest % + depreciation % ) /100 = (5 +2 ) ÷ 100
» So , A F.C. = 3 × 10⁵ RS × ( 5+2 )/100 , = 21,000 RS .
» annual running charge ( A.R.C. ) = capital cost of plant × ( maintenance % + insurance rent % ) /100 ,
» A.R.C. = 3 × 10⁵ RS × ( 2 + 1.5 ) /100 = 10,500 RS ,
» Total annual charges= RS ( 21000 + 10500 ) , = RS 31500 ,
» now , 2 nd in formula = unit reaching the consumer = unit generated per annum × ( 100% - losses in transmission ) ,
» unit generated per annum = M.D. × L.F. × hours in a years ,
» M.D. = let installed capacity × 80% ,
» let installed capacity = 100 kW,
» M.D. = 100 KW × 80% = 80 KW ,
» So , unit generated= 80 kW × 40% × 8760 = 2,80,320 kWh ,
» now , unit reaching the consumer = 2,80,320 × ( 100-12.5% losses), = after calculation = 2,45,280 kWh ,
= Annual running charge = annual running charge ÷ unit reaching the consumer , = 10500 rs ÷ 2,45,280 kWh , = 0.043 rs /kWh , answer.
=The generation cost in two part from is = rs ( 210 kw + 0.043 × kWh ) ,
= Total annual charges= RS ( 21000 + 10500 ) , = RS 31500 ,
» cost per kWh = 31500÷2,45,280, rs 0.128 or 12.8 paise answer ✓
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