Power station 28

 Question = A base load station having a capacity of 18 megawatt and a stand by station having a capacity of 20 megawatt . Share a common load . Find the annual load factor and plant capacity factor of two power station from the following data :

 Annual stand by station output = 7.35 × 10⁶ kWh ,  

Annual base load station output = 101.35 ×10⁶ kWh.

 Peak load on station = 12 MW , hours of use by standby station per year  = 2190 hours 

» Solution = Standby station : 

» annual load factor = ( unit generated per annum ) ÷ ( maximum demand × annual working hours ) , 

» peak loads एक तरह का maximum demand होता है । 

» So , A.L.F. = ( 7.35 × 10⁶ kWh ) ÷ ( 12 × 10³ × 2190 hours ) =0.28 , 

» for % ( × 100 ) = 0.28 × 100 = 28 % , answer ✓ 

» Annual plant capacity factor = ( unit generated per annum ) ÷ ( installed capacity × hours in a years ) , 

» A.P.L.F.= ( 7.35 × 10⁶ kWh ) ÷ ( 20 × 10³ × 8760 hours ) , = 0.0419 , 

» for % ( × 100 ) = 0.0419 × 100 = 4.19 % , answer ✓ 

(2) Base load station

» It is reasonable to assume that the maximum demand on the base load station is equal to the installed capacity ( 18 MW ) . It operates throughout the year for 8760 hours . 

» So , annual load factor = ( kWh output per annum ) ÷ ( installed capacity × hours in a years ) , 

» ( 101.35 × 10⁶ kWh ) ÷ ( 18 × 10³ kW × 8760 hours ) , = after calculate = 0.642 , 

» for % ( × 100 ) = 0.642 × 100 = 64.2 % , answer ✓ 

» as the base load station has no reserves above peak load and it is in continuous operation , therefore , its capacity factor is also 64.2 % . answer ✓ 

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