Power station 27

 Question = A generating station is to supply four regions of load whose peak loads are 10 megawatt , 5 megawatt , 8 megawatt and 7 megawatt  . the diversity factor at the station is 1.5 and the average annual load factor is 60% .  (1) Calculate the maximum demand on the station . ? (2) Annual energy supply by the station ? (3) Suggest the installed capacity and the number of unit ?

» Solution = (1) maximum demand = sum of maximum demand of the regions ÷ Diversity factor , 

» M D. = ( 10 + 5 + 8 +7 ) ÷ 1.5 = 20 MW , answer ✓ 

(2) unit generated per annum = M.D. × L.F. × hours in a years , 

» unit generated = 20 × 10³ × 0.6 × 8760 kWh , = 105.12 × 10⁶ kWh , answer ✓

(3) The installed capacity of the station should be 15 % to 20 % more than the maximum demand in order to meet the future growth of load . Tracking install capacity to be 20% more than the maximum demand .

» So , installed capacity = maximum demand का 20 % ,  = 20 MW × 20% , = 4 MW , 

» Capacity = 20 MW + 4 = 24 MW ,

» यहां peak loads 5 MW सबसे कम है , इसके हिसाब से 6 MW का DG set लेना होगा जिसकी संख्या 4 (6 MW × 4 = 24 MW ) होगी । ( 24 MW - 20 MW= 4 MW ) 4 MW power reserve में रख सकते हैं ।  Answer ✓