Power station 25

 Question = A Central station is supplying energy to a community through two substations . Each substation feeds 4 feeders . The maximum daily recorded demands are :

•  power station is maximum demand 12,000 kW . 

Sub Station A = maximum demand 6000 kW , 

Feeder no. 1 , 1700 kW , feeder no 2, 1800 kW , feeder no 3 , 2800 kW , feeder no 4 600 kW , 

• Sub Station B = maximum demand 9000 kW , 

Feeder no. 1 , 2820 kW , feeder no 2 , 1500 kW , feeder no 3 , 4000 kW, feeder no 4 , 2900 kW , 

Calculate the diversity factor between (1) Central substations , (2) feeder on substation A  , (3) feeders on substation B . ?

Solution =

 (1) Diversity factor of central station = ( maximum demand on substation A + maximum demand on substation B ) ÷ maximum demand of central station , 

» ( 6000 kW + 9000 kW )  ÷ 12,000 kW , = 15,000 ÷ 12,000 = 1.25 , answer ✓ 

(2) Diversity factor of substation A = sum of individual load substation A ÷ maximum demand substation A , 

» sum of individual load substation A  = 1700 + 1800 + 2800 + 600 kW , = 6900 kW , 

» maximum demand substation A = 6000 kW , 

» So , diversity factor = 6900 ÷ 6000 = 1.15 , answer ✓ 

(3) Diversity factor of substation B = sum of individual load substation B ÷ maximum demand substation B , 

» sum of individual load substation A = 2820 + 1500 + 4000 + 2900 kW = 11,220 kW , 

» maximum demand substation B = 9000 kW , 

» So , diversity factor = 11,220 ÷ 9000 , = 1.24 , answer ✓ 

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