Power station 9

 Question = It has been desired to install a diesel power station to supply power in a suburban . (1) 1000 houses with average connected load of 1.5 kW in each house . The demand factor 0.4 and diversity factor 2.5 respectively . (2) 10 factories having overall maximum demand of 90 kw .  (3) 7 tubewell of 7 kW each and operating together in the morning . 

The diversity factor among above three types of consumers is 1.2 .what should be the minimum capacity of power station ? .

Solution = formula = minimum capacity of station/power required = the sum of maximum demand of three types of loads ÷ diversity factor of three types of consumers , 

» maximum demand of three types of loads 1 = ( connected load × demand factor ) ÷ ( diversity factor of load 1 ) , 

» ( 1.5 kW × 0.4 ) × 1000  ÷ 2 .5 , = 240 kw , 

» maximum demand of factories = 90 kw , 

» maximum demand of tubewell = 7 × 7 = 49 kw , 

» So , the sum of maximum demand of three types of loads = 240 +90 + 49 , = 379 kw , 

» So ,  minimum capacity of station/power required = 379 ÷ 1.2 = 316 kw , answer ✓ 

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