Power station 7

 Question = A power supply is having the following loads :

• Domestic load = maximum demand 1500 kW , diversity of group 1.2 , Demand factor 0.8 , 

• commercial load = 2000 kW , Diversity of group 1.1 , Demand factor 0.9 , 

• Industrial load = maximum demand 10,000 kW , diversity of group 1.25 , demand factor 1 ,

If the overall system diversity factor is 1.35 determine , (1) the maximum demand and (2) connected load of each type . 

Solution = the sum of maximum demand of three type of loads is = 1500 + 2000 + 10,000 = 13,500 kw , 

As the system diversity factor is 1.35 , 

» maximum demand on supply system = 13,500/1.35 = 10,000 kW , answer ✓ 

(2) Each type of load has its own diversity factor among its consumers . 

» sum of maximum demands of different domestic consumer = maximum domestic demand ×  diversity factor , = 1500 × 1.2/0.8 = 2250 kW , answer ✓

» connected commercial load = 2000 × 1.1/0.9 , = 2444 kW, answer ✓ 

» connected industrial load = 10,000 × 1.25/1 , = 12,500 kW , answer ✓ 

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