Power station 10

 Question = A generating station has the following daily load cycles :


Draw the load curve and (1) maximum demand , (2) unit generated/day , (3) average load (4) load factor . ? 

Solution = Daily load curve is drawn by taking the load a long y- axis time a long x- axis. For the given load cycle , the load curve is show in figure . 


(1) it is clear from the load curve that maximum demand on the power station is 70 MW and occurs during the period 16 to 20 hours . So , maximum demand = 70 MW , answer ✓ 

(2) unit generated/day = MW × hours , 

»  [ 40 × 6 + 50 × 4 + 60 × 2 + 50 × 4 + 70 × 4 + 40 × 4 ] MWH , 

» [ 240 + 200 + 120 + 200 + 280 + 160 ] MWH , » 1200 MWH , 

» ÷ 1000 for kWh = 12 × 10⁵ kWh , answer ✓ 

(3) average load =unit generated/day ÷ 24 hours , 

» ( 12 × 10⁵ )  kWh ÷ 24 hours, = 50,000 kw , answer ✓ 

(4) load factor = average load ÷ maximum demand

» 70 MW or , 70 × 10³ kW , 

» 50,000 kW ÷ ( 70 × 10³ ) kW , = 0.714 or , 71.4 % , answer ✓ 

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