Alternator calculation part 2
Question = एक 8 pole का ac generator 750 rpm पर घूम रहा है । ( 1) इसकी frequency कितनी होगी ? (2) इसको किस speed पर घुमाया जाए कि frequency 40 c/s हो जाए ।
Solution = is given ,
(1) P = 8 , N = 750 rpm , F = ? ,
तो formula , F = N × P / 120 , = 8 × 750 / 120 , = 50 c/s , answer ✓
(2) F = 40 c/s , P = 8 , N = ? तो formula
N= 120 × F / P , = 120 × 40 / 8 , = 600 rpm , answer ✓
( rpm कम करने से frequency भी कम हो जायेगी )
(2) Question = एक ac generator की frequency 50 c/s हैं । जब वह 600 rpm पर घूम रहा है , इसके कितने pole होंगे ?
Solution = is given ,
F = 50 c/s , N = 600 rpm , p = ? ,
Formula = P = 120 × f / N , = 120 × 50/600 ,
» 10 pole , answer ✓
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