Power station 3

 Question = A 100 megawatt power station delivers 100 megawatt for 2 hour , 50 megawatt for 6 hour and is shut down for the rest of each day .  it is also shut down for maintenance for 45 days each year .  calculate the annual load factor ? 

• Solution = • max. demand = 100 MW , • 1 st Watt hour = 100 MW × 2 H , mwh • 2 nd watt hour = 50 MW × 6 H , mwh • 

Formula:

» annual load factor = ( mwh supplied per annum ) ÷ ( max. demand in MW × working hours ) ×100 ,

» station operates for in a year = 365 - 45 = 320 days , 

» MWH/energy supplied per annum = energy supplied for each working day × day operates in a year , 

» energy supplied for each working day = (100 × 2 ) + ( 50 ×6 )  = 500 mwh , 

» MWH or , energy supplied/year = 500 mwh × 320 = 1,60,000 MWH , 

» annual load factor =( energy supplied/year  ) ÷ ( max. demand ) × ( 320 days × 24 hours ) *× 100 ( for % ) ,  

» a.l.f. = ( 1,60,000 MWH ) ÷ ( 100 MW ) × ( 320 days × 24 hours )  × 100 (for % ) = 20.8 % , answer ✓